Download Lagu If A B C=180° then prove that: sin(B 2C) sin(C 2A) sin(A 2B) = 4sin(B-C)/2.sin(C-A)/2.sin(A-B)/2. MP3 & MP4
02 December 2022
Mr. Bidur Bastola
17:26
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If A B C=180° then prove that: sin(B 2C) sin(C 2A) sin(A 2B) = 4sin(B-C)/2.sin(C-A)/2.sin(A-B)/2.
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