Download Lagu show that `[[(a^2 b^2)/c,c,c],[a,(b^2 c^2)/a,a],[b,b,(a^2 b^2)/c]] = 4abc` MP3 & MP4
11 October 2018
Doubtnut
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show that `[[(a^2 b^2)/c,c,c],[a,(b^2 c^2)/a,a],[b,b,(a^2 b^2)/c]] = 4abc`
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